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y^2-130y+3325=0
a = 1; b = -130; c = +3325;
Δ = b2-4ac
Δ = -1302-4·1·3325
Δ = 3600
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{3600}=60$$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-130)-60}{2*1}=\frac{70}{2} =35 $$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-130)+60}{2*1}=\frac{190}{2} =95 $
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